X-Git-Url: https://code.communitydata.science/stats_class_2019.git/blobdiff_plain/dbde6a6880af749afd92848e06128fe161159d0b..fb2e2b741c48f616bb32e074de43048e315875a7:/problem_sets/week_03/ps3-worked_solution.Rmd

diff --git a/problem_sets/week_03/ps3-worked_solution.Rmd b/problem_sets/week_03/ps3-worked_solution.Rmd
index 76e2c63..35756c3 100644
--- a/problem_sets/week_03/ps3-worked_solution.Rmd
+++ b/problem_sets/week_03/ps3-worked_solution.Rmd
@@ -29,7 +29,7 @@ Now, I'll go ahead and load the CSV file into R. As with last week, I'll do this
 ### list.files("data/week_03") # just take a look around
 ### w3.data <- read.csv("data/week_03/group_01.csv")
 
-w3.data <- read.csv(url("https://communitydata.cc/~ads/teaching/2019/stats/data/week_03/group_02.csv"))
+w3.dtata <- read.csv(url("https://communitydata.cc/~ads/teaching/2019/stats/data/week_03/group_02.csv"))
 ```
 
 ### PC3. Get to know your data! 
@@ -143,7 +143,7 @@ Inspecting the first few values returned by `head()` gave you a clue. Rounded to
 I can create a table comparing the sorted rounded values to check this.
 ```{r}
 
-table(sort(round(w2.data, 6)) == sort(round(w3.data$x, 6)))
+table(round(w2.data,6) == round(w3.data$x,6))
 ```
 
 Can you explain what each piece of that last line of code is doing?
@@ -200,7 +200,7 @@ head(w3.data)
 lapply(w3.data, summary) 
 
 ### Run this line again to assign the new dataframe to p
-p <- ggplot(w3.data, aes(x=x, y=y))
+p <- ggplot(data=w3.data, mapping=aes(x=x, y=y))
 
 p + geom_point(aes(color=j, size=l, shape=k))
 ```
@@ -302,6 +302,6 @@ choose(10,2)*0.07^2*0.93^8
 
 (d) Is random assignment to tents likely to ensure $\leq1~arachnophobe$ per tent?
    
- Random assignment and the independence assumption means that the answer to part c is the inverse of the outcome we're looking to avoid: $P(\gt1~arachnophobes) = 1-P(\leq1~arachnophobe)$. So, $P(\gt1~arachnophobes) = 1-0.84 = 0.16 = 16\%$. Those are the probabilities, but the interpretation really depends on how confident the camp counselor feels about a $16\%$ chance of having multiple arachnophobic campers in one of the tents.
+ Random assignment and the independence assumption means that the answer to part c is the complement of the outcome we're looking to avoid: $P(\gt1~arachnophobes) = 1-P(\leq1~arachnophobe)$. So, $P(\gt1~arachnophobes) = 1-0.84 = 0.16 = 16\%$. Those are the probabilities, but the interpretation really depends on how confident the camp counselor feels about a $16\%$ chance of having multiple arachnophobic campers in one of the tents.